기초전자기학 3판 解法(해법) David J. Griffiths Introduction To Electrodynamics S…
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기초전자기학 3판 David J. Griffiths Introduction To Electrodynamics Solutions 解法(해법) 입니다.총 253페이지 입니다.. , 기초전자기학 3판 솔루션 David J. Griffiths Introduction To Electrodynamics Solutions전기전자솔루션 , 기초전자기학 3판 David J Griffiths Introduction To Electrodynamics Solutions 솔루션
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INSTRUCTOR`S SOLUTIONS MANUAL
INTRODUCTION to ELECTRODYNAMICS
Third Edition
David J. Griffiths
Errata Instructor’s Solutions Manual Introduction to Electrodynamics, 3rd ed Author: David Gri?ths Date: September 1, 2004 ? Page 4, Prob. 1.15 (b): last expression should read y + 2z + 3x. ? Page 4, Prob.1.16: at the beginning, insert the following ?gure
? Page 8, Prob. 1.26: last line should read From Prob. 1.18: ∇ × va = ?6xz x + 2z y + 3z 2 ? ⇒ ? ? z ∇ · (∇ × va ) =
∂ ∂x (?6xz)
+
∂ ∂y (2z)
+
∂ 2 ∂z (3z )
= ?6z + 6z = 0.
? Page 8, Prob. 1.27, in the determinant for ∇×(∇f ), 3rd row, 2nd column: change y 3 to y 2 . ? Page 8, Prob. 1.29, line 2: the num…(skip)
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기초전자기학 3판 解法(해법) David J. Griffiths Introduction To Electrodynamics Solutions
다.
기초전자기학 3판 David J. Griffiths Introduction To Electrodynamics Solutions 솔루션 입니다.
